To solve for the width \( w \) in the formula for the volume of a box \( V = lwh \), you would rearrange the equation as follows:
- Start with \( V = lwh \).
- To isolate \( w \), divide both sides by \( lh \):
\[
w = \frac{V}{lh}
\]
When you are talking about the units involved in this rearrangement, you start with volume \( V \) (in cubic inches, \( \text{in}^3 \)) and divide it by the product of length and height (each in inches, so \( \text{in} \times \text{in} = \text{in}^2 \)). Hence, the units for \( w \) would be:
\[
w = \frac{\text{in}^3}{\text{in}^2} = \text{in}
\]
From the choices given, the best representation of the remaining units would be:
a: \( \frac{\text{in}^3}{\text{in}^2} = \text{in} \) (or \( \text{in}^3 / \text{in}^2 = \text{in} \)).