Using the properties of equality, find the solution to the equation 2f5−85+2f=8.(1 point)

Responses

12
12

83
Start Fraction 8 over 3 End Fraction

4
4

166

1 answer

To solve the equation \( 2f^5 - 85 + 2f = 8 \), let's simplify and isolate \( f \).

  1. Move constants to the other side of the equation: \[ 2f^5 + 2f - 85 = 8 \]

  2. Add 85 to both sides: \[ 2f^5 + 2f = 93 \]

  3. Now, we can set this equation to zero: \[ 2f^5 + 2f - 93 = 0 \]

Next, we can try factoring or finding roots but since this is a polynomial of degree 5, we can attempt a numerical method such as trying out the given responses.

Let's test the possible solutions one by one.

  1. Testing \( f = 12 \): \[ 2(12)^5 + 2(12) = 2(248832) + 24 = 497664 + 24 = 497688 \quad \text{(not equal to 93)} \]

  2. Testing \( f = 4 \): \[ 2(4)^5 + 2(4) = 2(1024) + 8 = 2048 + 8 = 2056 \quad \text{(not equal to 93)} \]

  3. Testing \( f = \frac{8}{3} \): \[ 2 \left( \frac{8}{3} \right)^5 + 2 \left( \frac{8}{3} \right) \text{ - first calculate } \left( \frac{8}{3} \right)^5 \] \[ \left( \frac{8}{3} \right)^5 = \frac{32768}{243}, , \text{so } 2 \left( \frac{8}{3} \right)^5 = \frac{65536}{243} \] \[ 2 \left( \frac{8}{3} \right) = \frac{16}{3} \] Adding these: \[ \frac{65536}{243} + \frac{16}{3} = \frac{65536}{243} + \frac{1296}{243} = \frac{66832}{243} \text{ (not equal to 93)} \]

  4. Testing \( f = 166 \): \[ 2(166)^5 + 2(166) \]

However, typically, we would stop testing when a solution is located, but here:

After checking these options through, none yield solutions that satisfy \( 2f^5 + 2f = 93 \).

Given the original question's context, significant roots may be omitted here, so if forced by numerical guessing or a search method, you may need to refer to graphical or numerical resolution methods, but none of these common answer choices yield a resolution.

Could you double-check the equation or possible options you have? There might be a misalignment in transmitted values.