Using the Product Rule of Exponents, what is an equivalent form of 1^9⋅1^8?(1 point)

Question

base = , exponent =

Answer 1

Using the Product Rule of Exponents, which states that \( a^m \cdot a^n = a^{m+n} \), we can simplify the expression \( 1^9 \cdot 1^8 \).

Here, both bases are 1, so we apply the rule:

\[ 1^9 \cdot 1^8 = 1^{9 + 8} = 1^{17} \]

Thus, the equivalent form of \( 1^9 \cdot 1^8 \) is:

• base = 1
• exponent = 17