Using the procedure of comlpeting the square, write the equation x^2+y^2-6x+8y=0 in the form (x-h)^2+(y-k)^2=r^2.

Question

state the domain and range
where(h,k) is the center of the circle and r is the radius

Answer 1

first,

(x^2-6x + ?)+(y^2+8y+?)=?

we need (-3)^3 in the x, and 4^2 in the y

(x^2-6x+9)+(y^2+8y+16)=9+16

(x-3)^2 + (y+4)^2=5^2

Answer 2

how did u get -3^3 and 4^2?