To determine the force applied to the spring when an elongation of 2.3 meters is measured, we need to use the formula:
F = kx
Where:
F = Force applied to the spring
k = Spring constant (6.5 N/m)
x = Elongation (2.3 meters)
Plugging in the values:
F = (6.5 N/m) * (2.3 m)
F = 14.95 N
Therefore, the force applied to the spring when an elongation of 2.3 meters is measured is 14.95 Newtons.
Using the graph, determine the force applied to the spring if an elongation of 2.3 meters is measured. keep in mind the force is 6.5
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