Using the graph, derive the equation of the line in slope-intercept form (-2,2) (0,1)

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To find the equation of the line in slope-intercept form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept, we can follow these steps:

  1. Calculate the slope (m): The slope \(m\) is given by the formula:

    \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]

    Using the points \((-2, 2)\) and \((0, 1)\):

    \[ m = \frac{1 - 2}{0 - (-2)} = \frac{-1}{2} = -\frac{1}{2} \]

  2. Substitute the slope and one of the points into the point-slope form to find b: We'll use the point \((0, 1)\), which is also the y-intercept.

    Since the coordinates of this point are \(x = 0\) and \(y = 1\), we can directly see that \(b = 1\).

  3. Write the equation in slope-intercept form: Now that we have the slope and the y-intercept, we can write the equation of the line:

    \[ y = -\frac{1}{2}x + 1 \]

Thus, the equation of the line in slope-intercept form is:

\[ y = -\frac{1}{2}x + 1 \]

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