Using the given location of the right mass, at what location on the left side of the balance should a 2 kg mass be placed to make the balance level?

Question 7 options:

1 answer

To determine where to place a 2 kg mass on the left side of a balance to level it, we need to know the distance of the right mass from the fulcrum and the mass of that weight.

Let's assume the following:

  • The mass on the right side (\(m_r\)) is denoted as \(m_r\).
  • The distance from the fulcrum to the right mass is denoted as \(d_r\).
  • The mass on the left side (\(m_l\)) is 2 kg.
  • The distance from the fulcrum to the left mass is denoted as \(d_l\).

The balance will be level when the moments about the fulcrum are equal. This can be expressed with the following equation:

\[ m_r \cdot d_r = m_l \cdot d_l \]

Given \(m_l = 2 , \text{kg}\), we rearrange the equation to find \(d_l\):

\[ d_l = \frac{m_r \cdot d_r}{m_l} \]

To proceed, you must provide the specific values of \(m_r\) and \(d_r\). Once you have those values, you can calculate \(d_l\) to find the distance where the 2 kg mass should be placed on the left side of the balance to make it level.