A) The period of a function of the form f(x) = asin(bx) is determined by the formula T = 2π/b. In this case, the function is f(x) = 3sin(12θ), so the period is T = 2π/12 = π/2. Therefore, the period of the function is π/2.
The amplitude of the function is equal to the coefficient of sin(12θ), which is 3. Therefore, the amplitude of the function is 3.
B) To rewrite the function to have the same amplitude but with a period of π, we need to adjust the frequency of the function. Since T = 2π/b, we want to find the value of b that will give us a period of π. Therefore, b = 2π/π = 2.
Therefore, the rewritten function with the same amplitude and a period of π is f(x) = 3sin(2θ).
Using the function f(x)=3sin12θ
A) What are the period and amplitude of the function?
B) Rewrite the function to have the same amplitude, but with a period of π
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