The firework will explode at a height of 948 feet when it is fired with an initial velocity of v=1,056 ft/sec. To solve this problem, we can use the formula y=-16t^2+vt+h, where y is the height of the firework, t is the time it takes to reach the peak of its trajectory, v is the initial velocity, and h is the initial height.
We can rearrange the equation to solve for t: t = (v - sqrt(v^2 - 4(-16)(h-y)))/(2(-16)).
Plugging in the given values, we get t = (1,056 - sqrt(1,056^2 - 4(-16)(48-948)))/(2(-16)) = 4.5 seconds.
Therefore, the firework will explode at a height of 948 feet when it is fired with an initial velocity of 1,056 ft/sec.
Using the formula y=-16t^2+vt+h help me with this word problem : A firework rocket is fired straight up into the air with an initial velocity of v=192ft/sec
From the top of an apartment building h=48ft off the ground. The firework will explode when it reaches the peak (maximum) of its vertical trajectory. At what will the firework explode & with what initial velocity should the firework be fired to explode at the height of 948 feet?
1 answer
3 answers