I think the formula should read:
h=-16t^2+vt+s
Where s=initial height = 25'
v=initial velocity = 96 fps
t=time in seconds
-16=half of acceleration due to gravity in ft/s²
so the equation becomes
h(t)=-16t²+96t+25
solve for t when h(t)=0.
Using the formula
h=-16^2+vt+s
Answer the question: A rocket is shot upward off a 25 foot high balcony with an initial velocity of 96 feet per second. How many seconds will it take until the rocket hits the ground?
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