Look at the activity series. Which metal is above other metals.
Frankly I don't know what the question means. I will assume you want the strongest reducing agent.
I do that this way. There are much shorter ways of doing it but I like this one.
Cr is above Sn because Cr replaces Sn^2+.
Al is above Cr because Al replaces Cr^3+.
So the activity series will be
Al ==> Al^3+ + 3e
Cr ==> Cr3+ + 3e
Sn ==> Sn^2++ 2e
Notice that these are oxidations which means Al is easiest to oxidize. That makes Al the strongest reducing agent. If I have assumed incorrectly I'll try again if you rephrase the question.
. Using the following spontaneous reactions, classify the 3 metals involved (Cr, Sn, Al) according to increasing reductant properties.
a) 2Cr + 3Sn2+ ---> 2Cr3+ + 3Sn
b) Al + Cr3+ ---> Al3+ + Cr
1 answer
1 answer