no, find n for each. I will do one.
41,616= n(n+1)/2
83,232= n^2+n
put it in binomial form, and solve
n^2+n-83232=0
n= (-1+-sqrt 332929)/2= -1/2 +-288.5
n= 288, or n=-289
Now put them in the formula and verify. Normally, we restrict n to positive values, but your problem did not.
Now do the other number.
Using the following formula for a triangular number, verify that 1225 and 41 616 are triangular numbers. [Hint verify that there is an n for each number that satisfies the equation]
e.g., t5 = 15 =(5+1)/2
tn = n(n+1)/2
so, should I plug in 1225 and 41,616 and work the equation out? Somehow, I'm just reall confused by this problem. Could someone please be so kind as to help me?
5 answers
oh, okay! I'll try it out; thanks so much!
sorry, but I don't get where you're getting "n= (-1+-sqrt 332929)/2= -1/2 +-288.5" could you please explain?
1) I made an error in the next to last line.
n=0,180,360....the 1 was a typo.
Now, how did I get n. It came from the binomial equation for the quadratic form
if
ax^2+bx + c=0, then
x= (-b+-sqrt(b^2-4ac))/2a
n=0,180,360....the 1 was a typo.
Now, how did I get n. It came from the binomial equation for the quadratic form
if
ax^2+bx + c=0, then
x= (-b+-sqrt(b^2-4ac))/2a
oh... okay, thanks for the correction and the explanation
1 answer