f(1) = 5
f(5) = 35
(35 - 5) / (5 - 1) = ?
Using the exponential function 2^x + 3, what is the average rate of change between the values 1 ≤ x ≤ 5?
2 answers
that would, of course, be ∆y/∆x =
f(5)-f(1)
------------- = ((2^5+3)-(2^1+3))/4 = (35-5)/4 = 15/2
5-1
f(5)-f(1)
------------- = ((2^5+3)-(2^1+3))/4 = (35-5)/4 = 15/2
5-1