3 x² – 2 = 5 x
3 x² – 2 - 5 x = 0
3 x² - 5 x - 2 = 0
a x² + b x + c = 0
in this case:
a = 3 , b = - 5 , c = - 2
D = b² - 4 ∙ a ∙ c
D = ( - 5 )² - 4 ∙ 3 ∙ ( - 2 )
D = 25 + 4 ∙ 3 ∙ 2
D = 25 + 24
D = 49
If D > 0, the equation has 2 real solutions.
If D = 0, the equation has 1 real solution.
If D < 0, the equation has 2 conjugate imaginary solutions.
In this case D > 0 , so the equation has 2 real solutions.
Using the discriminant, how many real number solutions does this equation have?
3x^2 – 2 = 5x
1 answer
1 answer