Using the data in the table below, calculate the standard enthalpy change, in kJ mol-', for the reaction between carbon

disulfide,CS2, and oxygen shown in the following equation.

CS,(g) + 302(g) → CO₂(g) + 250₂(g)

Substance
CS₂(g)
CO₂(g)
SO₂(g)

Standard enthalpy change of formation, AH,/kJ mol-¹
+110
-390
-290

A) -570
B )-790
C )-860
D )-1080

1 answer

To calculate the standard enthalpy change for the reaction, we can use the equation:

ΔH = ΣnΔHf(products) - ΣnΔHf(reactants)

Where:
ΔH is the standard enthalpy change for the reaction
ΣnΔHf(products) is the sum of the standard enthalpy changes of formation for the products, multiplied by their stoichiometric coefficients
ΣnΔHf(reactants) is the sum of the standard enthalpy changes of formation for the reactants, multiplied by their stoichiometric coefficients

In this case, the stoichiometric coefficients for CS2, O2, CO2, and SO2 are 1, 3, 1, and 1 respectively.

Plugging in the values from the table:

ΔH = [1*(-390) + 1*(0)] - [1*(110) + 3*(0)]
ΔH = -390 - 110 = -500 kJ/mol

Therefore, the correct answer is not listed.