a) From moles acetic acid = moles NaOH
(acetic acid) = moles/100 g soln.
b) mass percent = moles acetic acid/100 g soln.
Using the data collected for part c on your data sheet and assuming the density of the vinegar is 1.00g/mL,
1) calculate the molar concentration of acetic acid (CH3COOH) in the vinegar sample using the average volume of NaOH.
2) calculate the mass percent of acetic acid in the vinegar sample.
Average volume NaOH: 28.94mL
Volume of vinegar: 5.00mL
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