Part 1:
First, we need to use the molar ratio between C2H4 and CO2 from the balanced equation, which is 1 mol C2H4 to 2 mol CO2.
7.5 mol C2H4 x (2 mol CO2 / 1 mol C2H4) = 15 mol CO2
Next, we need to convert the 15 mol of CO2 to grams:
15 mol CO2 x 44.01 g/mol = 660.15 g CO2
Therefore, 660 g of CO2 are formed from 7.5 mol of C2H4.
Part 2:
Using the molar ratio between C2H4 and H2O from the balanced equation, which is 1 mol C2H4 to 2 mol H2O.
0.84 mol C2H4 x (2 mol H2O / 1 mol C2H4) = 1.68 mol H2O
Next, we need to convert the 1.68 mol of H2O to grams:
1.68 mol H2O x 18.02 g/mol = 30.336 g H2O
Therefore, 30 g of H2O are formed from 0.84 mol of C2H4.
Using the balanced equation for the combustion of ethylene (C2H4), answer the following questions.
C2H4 + 302 - 2CO2 + 2H20
Be sure each of your answer entries has the correct number of significant figures.
Part 1 of 2
10
How many grams of CO2 are formed from 7.5 mol of C2H4?
g CO2
X
Part 2 of 2
How many grams of H2O are formed from 0.84 mol of C2H4?
g H2O
10
this is not correct
1 answer