For the first question, we need to use the stoichiometry of the reaction to determine the grams of CO2 formed from 7.5 mol of C2H4.
From the balanced equation, we see that 1 mol of C2H4 produces 2 mol of CO2. Therefore, we can set up the following stoichiometry calculation:
7.5 mol C2H4 x (2 mol CO2 / 1 mol C2H4) x (44.01 g CO2 / 1 mol CO2) = 660.15 g CO2
Therefore, 7.5 mol of C2H4 will produce 660.15 grams of CO2.
For the second question, we can follow a similar stoichiometry calculation to find the grams of H2O formed from 0.86 mol of C2H4.
0.86 mol C2H4 x (2 mol H2O / 1 mol C2H4) x (18.02 g H2O / 1 mol H2O) = 31.04 g H2O
Therefore, 0.86 mol of C2H4 will produce 31.04 grams of H2O.
Using the balanced equation for the combustion of ethylene (C2H4), answer the following questions.
C2H4 + 302 - 2CO2 + 2H20
Be sure each of your answer entries has the correct number of significant figures.
Part 1 of 2
10
How many grams of CO2 are formed from 7.5 mol of C2H4?
g CO2
How many grams of H2O are formed from 0.86 mol of C2H4?
g H2O
1 answer