To cancel out the x variables, we need to multiply one of the equations by a factor that will make the coefficient of x in one equation equal to the coefficient of x in the other equation, but with opposite signs.
Let's choose the second equation and multiply it by 2 to get:
12x + 4y = 120
Now we have two equations:
3x + 4y = 48
12x + 4y = 120
To eliminate the y variables, we can subtract the first equation from the second equation:
(12x + 4y) - (3x + 4y) = 120 - 48
12x - 3x + 4y - 4y = 72
9x = 72
Now, we can solve for x:
9x = 72
x = 72 / 9
x = 8
Now that we have found the value of x, we can substitute it back into one of the original equations to find the value of y. Let's use the first equation:
3x + 4y = 48
3(8) + 4y = 48
24 + 4y = 48
4y = 48 - 24
4y = 24
y = 24 / 4
y = 6
So the solution to the system of equations is x = 8 and y = 6.
Using substitution how could you get x variables to cancel out?
3x+4y=48 and 6x+2y =60
1 answer
1 answer