To evaluate the statements involving square roots and rational approximations, let's simplify and compare each part step-by-step:
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Square root of 49: \[ \sqrt{49} = 7 \]
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Square root of 48: \[ \sqrt{48} \approx 6.928 \quad (\text{since } 48 \text{ is between } 36 \text{ and } 49) \]
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Square root of 36: \[ \sqrt{36} = 6 \]
Now we can compare the values:
- \( \sqrt{49} = 7 \) and \( 7 \) is not less than \( 7 \), so the first statement "square root of 49 is less than seven" is false.
- Now considering \( \sqrt{48} \approx 6.928 \) and \( \sqrt{36} = 6 \): \[ \sqrt{48} \approx 6.928 > 6 = \sqrt{36} \]
Thus, the comparison \( \sqrt{48} > \sqrt{36} \) is true.
Now let's summarize:
- \(\sqrt{49} < 7\) is false.
- \(\sqrt{48} < \sqrt{36}\) is false.
- \(\sqrt{49} > 7\) is false.
- \(\sqrt{48} > \sqrt{36}\) is true.
Therefore, the correct statement is "the square root of 48 is greater than the square root of 36."