Using rational approximations, what statement is true?

√49>7

√49<7
√48>√36

√48<√36

3 answers

To evaluate the statements, let's analyze each one carefully:

  1. √49 > 7:

    • We know that √49 = 7. Therefore, this statement is false.
  2. √49 < 7:

    • Since √49 = 7, this statement is also false.
  3. √48 > √36:

    • We know that √36 = 6. To find √48, we can recognize that √48 is approximately √(4×12) = 2√12. The value of √12 is around 3.464, so 2√12 is approximately 6.928. Since 6.928 > 6, this statement is true.
  4. √48 < √36:

    • Given that √48 > 6, this statement is false.

From the analysis above, the true statement is:

√48 > √36.

are you sure

Let's carefully reevaluate the comparisons to ensure accuracy.

  1. √49 > 7:

    • √49 = 7, so this is false.
  2. √49 < 7:

    • Again, since √49 = 7, this is false.
  3. √48 > √36:

    • We know that √36 = 6. Now for √48, we can simplify it to: \[ \sqrt{48} = \sqrt{16 \times 3} = 4\sqrt{3} \]
    • We know that √3 is approximately 1.732. Therefore, \[ 4\sqrt{3} \approx 4 \times 1.732 \approx 6.928 \]
    • Since 6.928 > 6, this statement is true.
  4. √48 < √36:

    • This is the opposite of the prior statement, and since we've established that √48 > √36, this is false.

So, to confirm, the statement that is true is indeed:

√48 > √36.

Thank you for your patience, and the conclusion remains accurate.

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