To determine which statement is true, we can evaluate the square root of 12 and the square root of 16, and compare them with π (approximately 3.14) and 4.
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Calculate \(\sqrt{12}\): \[ \sqrt{12} \approx 3.464 \] We compare \(3.464\) with \(\pi\) (approximately \(3.14\)): \[ 3.464 > 3.14 \quad (\text{So } \sqrt{12} > \pi) \]
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Calculate \(\sqrt{16}\): \[ \sqrt{16} = 4 \] We compare \(4\) with \(4\): \[ 4 = 4 \quad (\text{So } \sqrt{16} \text{ is neither less than nor greater than } 4) \]
Based on these evaluations, we find:
- \(\sqrt{12} > \pi\)
- \(\sqrt{16} = 4\) (not less than and not greater than)
The correct statement is: \[ \sqrt{12} > \pi \]
Thus, the true statement is: \[ \sqrt{12} > \pi \]