To compare \(\sqrt{21}\) and \(\sqrt{17}\) using rational approximations, let's first find approximate values for both square roots.
-
\(\sqrt{21}\):
- We know that \(4^2 = 16\) and \(5^2 = 25\), so \(\sqrt{21}\) is between 4 and 5.
- A more precise approximation can be obtained by estimating: \[ 4.5^2 = 20.25 \quad \text{(too low)} \] \[ 4.6^2 = 21.16 \quad \text{(too high)} \]
- Thus, \(\sqrt{21} \approx 4.58\).
-
\(\sqrt{17}\):
- Similarly, since \(4^2 = 16\) and \(5^2 = 25\), \(\sqrt{17}\) is also between 4 and 5.
- A more precise approximation: \[ 4.1^2 = 16.81 \quad \text{(too low)} \] \[ 4.2^2 = 17.64 \quad \text{(too high)} \]
- So, \(\sqrt{17} \approx 4.12\).
Now, we compare the two approximations:
\[ \sqrt{21} \approx 4.58 \quad \text{and} \quad \sqrt{17} \approx 4.12 \]
Since \(4.58 > 4.12\), we conclude:
\[ \sqrt{21} > \sqrt{17} \]
Therefore, the inequality statement comparing \(\sqrt{21}\) and \(\sqrt{17}\) is:
\[ \sqrt{21} > \sqrt{17} \]
In the required format, the answer is:
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