To compare \(\pi\) and \(\sqrt{8}\), we can use rational approximations:
- We know that \(\pi\) is approximately equal to \(3.14\).
- To calculate \(\sqrt{8}\): \[ \sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \cdot \sqrt{2} = 2\sqrt{2}. \] The approximate value of \(\sqrt{2}\) is about \(1.414\). Therefore, \[ 2\sqrt{2} \approx 2 \times 1.414 \approx 2.828. \]
Now we compare:
- \(\pi \approx 3.14\)
- \(\sqrt{8} \approx 2.828\)
We can see that: \[ \pi > \sqrt{8} \]
Thus, the inequality statement is: \[ \pi \ > \ \sqrt{8} \]
So, the answer is: \(\pi \ \square \ \sqrt{8}\) where \(\square\) is \(>\).