Using -pi/2 ≤ y ≤ pi/2, what are the following solutions?

Question

y=arcsin root3/2

y=arcsin 1/2

Answer 1

for both cases, since for any -π/2 < y < 0 the sine will be negative, we only have to concern ourself with angles in the first quadrant.

so if y = arcsin (√3/2)
then y = π/3 ( I know sin 60° = sin π/3 = √3/2 )
and for the second one

y = π/6