Asked by d
Using numerical analysis and the Power Rule of Logarithms, log x^k=k log x
, how can log(1/100)
be rewritten?(1 point)
Responses
−2log10
negative 2 logarithm 10
2log−10
2 logarithm negative 10
10log−2
10 logarithm negative 2
log−20
, how can log(1/100)
be rewritten?(1 point)
Responses
−2log10
negative 2 logarithm 10
2log−10
2 logarithm negative 10
10log−2
10 logarithm negative 2
log−20
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To rewrite \( \log(1/100) \) using the Power Rule of Logarithms, we can follow these steps:
1. Recognize that \( \frac{1}{100} \) can be expressed as \( 100^{-1} \).
2. Apply the log property: \( \log(a/b) = \log a - \log b \).
3. Thus, we have:
\[
\log(1/100) = \log(100^{-1}) = -1 \cdot \log(100).
\]
4. Since \( 100 = 10^2 \), we can further write:
\[
\log(100) = \log(10^2) = 2 \log(10).
\]
Combining these, we get:
\[
\log(1/100) = -1 \cdot 2 \log(10) = -2 \log(10).
\]
So, the correct numerical analysis is:
**−2log10 (negative 2 logarithm 10)**.
1. Recognize that \( \frac{1}{100} \) can be expressed as \( 100^{-1} \).
2. Apply the log property: \( \log(a/b) = \log a - \log b \).
3. Thus, we have:
\[
\log(1/100) = \log(100^{-1}) = -1 \cdot \log(100).
\]
4. Since \( 100 = 10^2 \), we can further write:
\[
\log(100) = \log(10^2) = 2 \log(10).
\]
Combining these, we get:
\[
\log(1/100) = -1 \cdot 2 \log(10) = -2 \log(10).
\]
So, the correct numerical analysis is:
**−2log10 (negative 2 logarithm 10)**.
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