Using molality and molarity to describe a solution Calculate the percent concentration of 125mg CuSO4 dissolved in enough water to make 5.00ml of solution

Answer 1

To calculate the percent concentration, we need to know the amount of CuSO4 in the solution and the total volume of the solution.

First, let's convert the given mass of CuSO4 to moles. The molar mass of CuSO4 is:

CuSO4 = 63.55 + 32.06 + 4(16.00) = 159.60 g/mol

125 mg CuSO4 = 125/1000 g CuSO4 = 0.125 g CuSO4

0.125 g CuSO4 x (1 mol CuSO4/159.60 g CuSO4) = 0.000783 mol CuSO4

Now, we need to find the total volume of the solution. We are given that 125 mg CuSO4 is dissolved in enough water to make 5.00 ml of solution.

The solution density is not given, but we can assume that the density of the solution is 1.00 g/mL. This means that the total mass of the solution is:

5.00 mL x 1.00 g/mL = 5.00 g

Now, we can convert the amount of CuSO4 to percent concentration:

Percent concentration = (amount of CuSO4 / total mass of solution) x 100%

Percent concentration = (0.000783 mol CuSO4 x 159.60 g/mol / 5.00 g) x 100%

Percent concentration = 2.50%

Therefore, the percent concentration of 125 mg CuSO4 dissolved in enough water to make 5.00 mL of solution is 2.50%.