Le Chatlier's Principle says that when a system at equilibrium is disturbed it will shift so as to undo what we've done it it.
AgBr in 0.1 M HBr.
......AgBr ==> Ag^|Using the balanced chemical equation, calculate the equilibrium constant for this system.
AgBr(s) ==> Ag^+(aq) + Br^-(aq)
(Note AgBr is only slightly soluble)
HBr ==> H^+ + Br^-.
(Note that HBr is a strong acid; it ionizes completely.)
So the AgBr is slightly soluble, it has dissolved as much as it can. When you add extra Br^- to it, it tries to get rid of the added Br^-. It can do that only one way. By shifting the equilibrium to the left; i.e., some of the Ag^+ in solution combines with some of the Br^- to form solid AgBr (in other words the rxn shifts to the left) and AgBr becomes less soluble when HBr is added.
The others are done the same way.
Note that in Fe(OH)2 and HCl that the HCl reacts to form H2O so you are removing OH^- from the solution. I'll be happy to review your answers.
using leChatlier's principle, which of following is more or less soluble in following solutions than in pure water. and explaination for each asked for. Compared to pure water are they less, more or same? thanks.
AgBr in 0.100M HBr
AgBr IN 0.100 m HNO3
Fe(Oh)2 in 0.100 M HCl
Fe(OH)2 in 0.100 M naoh
4 answers
yes, the first one i understood. It was more so when AgBr in HNO3, in an acid where i don't see a common ion. with the first one i calculated solubility mathematically even though i didn't need to. My answers are:
less soluble, more soluble, more, and less
less soluble, more soluble, more, and less
AgBr in HNO3 is no effect (or the same solubility).
You're right, there is no common ion and the only rxn that you need to consider is combination of H with Br. IF (and it isn't) HBr were a weak acid it would be more soluble but since HBr is a strong acid there is no driving force so solubility in HNO3 is the same as if no HNO3 were there.
You're right, there is no common ion and the only rxn that you need to consider is combination of H with Br. IF (and it isn't) HBr were a weak acid it would be more soluble but since HBr is a strong acid there is no driving force so solubility in HNO3 is the same as if no HNO3 were there.
Alright. It makes more sense to me now. Thank you!
1 answer