h(x)=0.5x-0.002x^2
h(x)=.5x(1-.004x^2)=.5/.004 * (x*(250-x^2)
when x=0, x=15.81 (ie, sqrt250), height is zero.
max height occurs at 15.81/2 feet downrange, figure that out from h(x)
Using his driver on the 7th tee, Chris hits an excellent shot, right down the middle of the fairway. The ball follows the parabolic path shown in the figure, described by the quadratic function: h(x)=0.5x-0.002x^2. This relates the height, h, of the ball above the ground to the distance x it has traveled down the course. Distances are measures in feet.
a) How high is the ball after it has traveled 20 feet horizontally down the course?
b) Factor the quadratic function that describes the ball’s path. Notice that x = 0 when x= 0. What is the physical meaning of this?
c) How far away from the tee does the ball hit the ground?
d) What is the ball’s maximum height above the ground and what distance x, from the tee, does this occur at?
Could you please teach me these problems..?
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