Using GRAPHICAL METHOD, find the vector sum of a force of 20 N directed 60 degrees east of north and a force of 60 N directed west? Please show all steps and equations used.

Question

Henry · Answer

Fr = 20N[30oCCW] + 60N[180oCCW] = Resultant force.

X = 20*Cos30 + 60*Cos180 = 17.3 - 60 = -42.7 N.
Y = 20*sin30 + 60*sin180 = 10 + 0 = 10 N.

Tan A = Y/X = 10/-42.7 = -0.23419.
A = -13.2o = 76.8o W. of N. = Direction.

Fr = sqrt(X^2 + Y^2) =

Note: This not a graphical method.