I'm sure I could solve this if your question made a bit more since.
What's with f^-1? That doesn't mean anything. Is it F^2-1?
Please clarify and you'll get your answer very fast. :)
using f(x)=4x-5, find
f^-1 o f
5 answers
it's f to the power of -1, then i think it's called composite f. Like you know when you get the problems fog of gof? it's like that except fof and the first f is raise to -1 power. Thanks
Ah I see!
Sorry for the blind-sightedness. :P
I believe your answer is
f(x)=1/4x-5
Sorry for the blind-sightedness. :P
I believe your answer is
f(x)=1/4x-5
No worries, Thank you
first of all,
if f(x) = 4x - 5 , then
f^-1(x) = (x+5)/4
then f^-1 o f = f^-1(f(x))
= f^-1(4x-5)
= ((4x-5) + 5)/4
= x
if f(x) = 4x - 5 , then
f^-1(x) = (x+5)/4
then f^-1 o f = f^-1(f(x))
= f^-1(4x-5)
= ((4x-5) + 5)/4
= x