Using energy considerations, calculate the average force a 60.0 kg sprinter exerts backward on the track to accelerate from 2.00 to 6.00 m/s in a distance of 25.0 m, if he encounters a headwind that exerts an average force of 30.0 N against him.

Answer 1

f=ma=60g*(6-2)/time

what is the time? avg velocity is 4, distance 25, time=25/4 seconds

force applied=30+60*g*4*4/24 N

Answer 2

5.77