Using change of variable to solve 2/3x^2-x-2 +5/3x^2-x-1=7/3x^2-x-3

2 answers

let u = 3x^2-x-2. Then you have

2/u + 5/(u+1) = 7/(u-1)
That gives you
u = -1/6

Now all you have to do is solve

3x^2-x-2 = -1/6
Combine terms.

The x^2 terms cancel out.

-2x-3 = -x-3

-x = 0

Do you have typos?