Using calories, how much heat will 32 grams of water absorb when it is heated from 25 C to 80 C?

Answer 1

q = heat absorbed = mass x specific heat water x (Tf - Ti) where
mass = 32 grams.
You will need to look up the specific heat of water. I think it's about 4 J/g*C.
Tf is final temperature. Ti is initial T.
Post your work if you get stuck.