Technically, no. Realistically, #1 is ok but not #2.
The technical part is that you didn't show the calorie as 1 cal/g*c but
32 x 1 x 55 = 1760 calories.
But you DIVIDED by 4.184 for #2, you should have multiplied by 4.184.
mass x specific heat x delta T.
Using calories, calculate how much heat 32.0g of water absorbs when it is heated from 25.0 degrees C to 80.0 degrees C. How many joules is this?
Are these steps right?
32.0g x 55*C = 1760 calories = 420.65 Joules
2 answers
Using calories, calculate how much heat 32.0g of water absorbs when it is heated from 25.0 degrees C to 80.0 degrees C. How many joules is this?
8 answers