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Using an appropriate linear approximation approximate 26.9^(4/3).

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27^(4/3) = 81
y = x^(4/3)
dy = (4/3)x^(1/3) dx
so, if dx = -0.1
dy = (4/3)(3)(-0.1) = -0.4
So, 26.9^(4/3) ≈ 80.6

In fact 26.9^(4/3) = 80.6002
pretty close, eh?

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