try using
x = tanθ
dx = sec^2θ dθ
see where that takes you!
Using a suitable substitution show that integrate {[ln|1+x|]/[1+(x)^2]} from 0-1 = (π/8)ln|2|
On this one, I don't really have any ideas of going forward solving this.I don't see a substitution which will simply the integral.
2 answers
That worked!!! Thank you very much!