angles B and C are easy to construct (google it if needed)
where the rays intersect is point A.
L1 is just the ⊥ bisector of BC
L2 is just a circle of radius 4cm with center at A
Using a ruler and a pair of compasses only
Construct;
1)the triangle ABC such that |BC|=10cm,<ABC=60⁰ and <ACB=45⁰
2)the locus L1 of point equidistance from B and C
3)The L2 of point 4cm from A
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