To find the distance from the jumping platform when the skateboarder is at their minimum height off the ground, we need to find the x-coordinate of the vertex of the parabolic function represented by the equation.
Given the equation y = 0.25x^2 - 4x + 19, the x-coordinate of the vertex is given by x = -b/(2a), where a = 0.25 and b = -4.
x = -(-4)/(2*0.25)
x = 4/0.5
x = 8
Therefore, the skateboarder is 8 feet away from the jumping platform when they are at their minimum height off the ground.
Using a certain ramp at the skate park, a skater’s height off the ground, in feet, is modeled by the equation y=0.25x2−4x+19 , where x is the skater’s horizontal distance from the jumping platform. How far from the jumping platform is a skateboarder when they are at their minimum height off the ground?(1 point)
1 answer
1 answer