a) An equation for the total cars and trucks for Dealership A:
Let x be the number of cars sold by Dealership A.
Let y be the number of trucks sold by Dealership A.
The equation would be: x + y = 225.
b) An equation for the total cars and trucks for Dealership B:
Let x be the number of cars sold by Dealership B.
Let y be the number of trucks sold by Dealership B.
The equation would be: 2x + (1/2)y = 300.
c) To find the number of cars sold by Dealership A, we can solve the equation x + y = 225.
You can do this on your graphing calculator by entering the equation and using the "solve" function.
The answer is 125 cars.
d) To find the number of trucks sold by Dealership B, we need to know the number of trucks sold by Dealership A.
Since it is given that Dealership B sold half as many trucks as Dealership A, we can double the number of trucks sold by Dealership A to find the number of trucks sold by Dealership B.
Double the number of trucks sold by Dealership A (y) = 2 * 125 = 250 trucks.
So, Dealership B sold 250 trucks.
Use your graphing calculator: Demos Graphing Calculator
A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 225 cars and trucks. Dealership B sells twice as many cars and half as many trucks as the Dealership A, and sells a total of 300 cars and trucks.
(4 points)
a) An equation for the total cars and trucks for Dealership A: (x+y=300 , x+y=225 , x+y=525)
b) An equation for the total cars and trucks for Dealership B: (1/2x +2y=225 , 1/2x + 1/2y=525 , 2x+ 1/2y=300)
c) How many cars did Dealership A sell? (196, 125, 132, 98)
d) Given the fact that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell? (49, 33, 98, 50)
1 answer