Use this to answer the question.

A graphed function starting on the x axis has an arrow at the other end passes through three points on a coordinate plane. The x-axis ranges from negative 9 to 9 in unit increments and the y-axis ranges from negative 11 to 11 in unit increments.

Which table shows that y=−f(x)
results in a reflection over the x-axis?

(1 point)
Responses

x −f(x)
2 0
3 −1
6 −2
x f left parenthesis x right parenthesis 2 0 3 negative 1 6 negative 2

x −f(x)
2 0
3 1
6 2 x f left parenthesis x right parenthesis 2 0 3 1 6 2

x −f(x)
−2
0
−3
−1
−6
−2
x f left parenthesis x right parenthesis negative 2 0 negative 3 negative 1 negative 6 negative 2

x −f(x)
−2
0
−3
1
−6
2 x f left parenthesis x right parenthesis negative 2 0 negative 3 1 negative 6 2
Skip to navigation

1 answer

To determine which table shows that \( y = -f(x) \) results in a reflection over the x-axis, we need to look for a table where the values of \( -f(x) \) are the negative counterparts of the values of \( f(x) \).

Let's examine each response:

    • For \( x = 2 \), \( f(2) = 0 \) and \( -f(2) = 0 \) (not a reflection)
    • For \( x = 3 \), \( f(3) = -1 \) and \( -f(3) = 1 \) (this shows reflection)
    • For \( x = 6 \), \( f(6) = -2 \) and \( -f(6) = 2 \) (this shows reflection)
    • For \( x = 2 \), \( f(2) = 0 \) and \( -f(2) = 0 \) (not a reflection)
    • For \( x = 3 \), \( f(3) = 1 \) and \( -f(3) = -1 \) (not a reflection)
    • For \( x = 6 \), \( f(6) = 2 \) and \( -f(6) = -2 \) (not a reflection)
    • For \( x = -2 \), \( f(-2) = -2 \) and \( -f(-2) = 2 \) (this shows reflection)
    • For \( x = 0 \), \( f(0) = 0 \) and \( -f(0) = 0 \) (not a reflection)
    • For \( x = -3 \), \( f(-3) = -1 \) and \( -f(-3) = 1 \) (this shows reflection)
    • For \( x = -6 \), \( f(-6) = -2 \) and \( -f(-6) = 2 \) (this shows reflection)
    • For \( x = -2 \), \( f(-2) = -2 \) and \( -f(-2) = 2 \) (this shows reflection)
    • For \( x = 0 \), \( f(0) = 0 \) and \( -f(0) = 0 \) (not a reflection)
    • For \( x = -3 \), \( f(-3) = 1 \) and \( -f(-3) = -1 \) (not a reflection)
    • For \( x = -6 \), \( f(-6) = 2 \) and \( -f(-6) = -2 \) (not a reflection)

From this analysis, the first option shows the necessary reflection for \( f(3) \) and \( f(6) \), and the third option also demonstrates the reflection for points within \( f(-2) \) and \( f(-3) \).

However, because the pairs in the first response demonstrate the reflection consistently under positive values, the response that best shows that \( y = -f(x) \) corresponds to a reflection over the x-axis is:

First Response (y = -f(x)):

  • For \( x = 2, -f(2) = 0 \)
  • For \( x = 3, -f(3) = 1 \)
  • For \( x = 6, -f(6) = 2 \)

So, I would select the first option as the answer.