Use this formula: a = F m 

Take Note: Acceleration due to gravity is 9.8 m/s2

A 500 kg car and rider accelerate at 13.5 m/s^2. How much extra force was applied?

What is the acceleration of a 50kg cart if the net force on it is 40N ?

What is the weight of a 80.2 kg person on the surface of the Earth?

A 75.0 kg person weighs 94.0 N on the Moon. What is the acceleration of gravity on the Moon?

50.0 kg Yuri Gagarin is freely floating in space and pushes on a freely floating 85.0 kg spacecraft with a force of 20.0 N for 2 seconds.

Compare the forces exerted by Yuri Gagarin and the spacecraft and,

1 answer

evaluate the resulting acceleration of the spacecraft.

To find the extra force applied in the first scenario, we use the formula:

a = F/m

Given:
m = 500 kg
a = 13.5 m/s^2

Substituting the values into the formula, we can rearrange to solve for F:

F = a * m
F = 13.5 m/s^2 * 500 kg
F = 6750 N

Therefore, an extra force of 6750 N was applied to the car and rider.

For the second scenario, to find the acceleration of a 50 kg cart with a net force of 40 N, we use the same formula:

a = F/m

Given:
m = 50 kg
F = 40 N

Substituting the values into the formula, we rearrange to solve for a:

a = F/m
a = 40 N / 50 kg
a = 0.8 m/s^2

Therefore, the acceleration of the cart is 0.8 m/s^2.

To find the weight of an 80.2 kg person on the surface of the Earth, we use the formula:

F = m * a

Given:
m = 80.2 kg
a = acceleration due to gravity = 9.8 m/s^2

Substituting the values into the formula, we can solve for F:

F = 80.2 kg * 9.8 m/s^2
F = 787.96 N

Therefore, the weight of the 80.2 kg person on the surface of the Earth is 787.96 N.

To find the acceleration of gravity on the Moon for the fourth scenario, we use the formula:

F = m * a

Given:
m = 75.0 kg
F = 94.0 N

Substituting the values into the formula, we can solve for a:

94.0 N = 75.0 kg * a
a = 94.0 N / 75.0 kg
a = 1.253 m/s^2

Therefore, the acceleration of gravity on the Moon is approximately 1.253 m/s^2.

For the fifth scenario, to compare the forces exerted by Yuri Gagarin and the spacecraft, we can calculate their respective accelerations:

a = F/m

Given:
For Yuri Gagarin: m = 50.0 kg, F = 20.0 N
For the spacecraft: m = 85.0 kg, F = 20.0 N

Substituting the values into the formula, we can calculate the respective accelerations:

For Yuri Gagarin:
a = 20.0 N / 50.0 kg
a = 0.4 m/s^2

For the spacecraft:
a = 20.0 N / 85.0 kg
a = 0.235 m/s^2

Comparing the forces, we see that both Yuri Gagarin and the spacecraft exert the same force, 20.0 N. However, the resulting accelerations are different, with Yuri Gagarin experiencing an acceleration of 0.4 m/s^2 and the spacecraft experiencing an acceleration of 0.235 m/s^2.