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use thermochemical equations shown below to determine enthalpy for the reaction: H2CO3-->H2O+CO2 1) H2CO3 --> H2CO + O2 H; 224...Asked by Brittany
use thermochemical equations shown below to determine enthalpy for the reaction:
H2CO3-->H2O+CO2
1) H2CO3 --> H2CO + O2 H; 224 KJ
2)H2CO + O2 --> H2O + CO2 H; -100KJ
I know this problem is one that you have to rewrite the equations to get the equation in the original question - but I am lost on how to go about it. Thanks!!
H2CO3-->H2O+CO2
1) H2CO3 --> H2CO + O2 H; 224 KJ
2)H2CO + O2 --> H2O + CO2 H; -100KJ
I know this problem is one that you have to rewrite the equations to get the equation in the original question - but I am lost on how to go about it. Thanks!!
Answers
Answered by
bobpursley
H2CO3>>H2CO+O2>>H2O+CO2
Hr= 224+(-100) Kj/mole
Hr= 224+(-100) Kj/mole
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