use thermochemical equations shown below to determine enthalpy for the reaction:

Question

H2CO3-->H2O+CO2

1) H2CO3 --> H2CO + O2 H; 224 KJ
2)H2CO + O2 --> H2O + CO2 H; -100KJ

I know this problem is one that you have to rewrite the equations to get the equation in the original question - but I am lost on how to go about it. Thanks!!

Answer 1

H2CO3>>H2CO+O2>>H2O+CO2

Hr= 224+(-100) Kj/mole