To balance the unbalanced chemical equation:
\[ 2 \text{NaHCO}_3 \rightarrow \text{Na}_2\text{CO}_3 + \text{CO}_2 \]
Let's first analyze the reactants and products:
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On the left side (reactants), there are:
- 2 Sodium (Na)
- 2 Carbon (C)
- 6 Oxygen (O)
- 2 Hydrogen (H)
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On the right side (products), there are:
- 2 Sodium (Na) (from Na2CO3)
- 2 Carbon (C) (1 from Na2CO3 and 1 from CO2)
- 3 Oxygen (O) (3 from Na2CO3 and 2 from CO2; total of 5)
- No Hydrogen (H)
To balance the equation, we can add H2O to the products, which will provide the necessary hydrogen and additional oxygen to complete the balance:
Adding one molecule of H2O on the products side:
\[ 2 \text{NaHCO}_3 \rightarrow \text{Na}_2\text{CO}_3 + \text{CO}_2 + \text{H}_2\text{O} \]
Now we can count again:
- Right side after the addition:
- Sodium: 2
- Carbon: 2 (1 in Na2CO3 and 1 in CO2)
- Oxygen: 6 (3 in Na2CO3, 2 in CO2, 1 in H2O; total of 6)
- Hydrogen: 2 (from H2O)
Now both sides are balanced:
- Sodium: 2
- Carbon: 2
- Oxygen: 6
- Hydrogen: 2
Thus, adding H2O is the appropriate choice to balance the equation. The answer is:
H2O