Use the tables to create scatterplots and determine which scatterplot shows a linear association.(1 point) Responses x 5.0 4.6 8.5 7.8 6.8 5.3 7.0 7.2 y 12.0 8.5 6.0 10.0 12.0 10.0 12.0 10.0 x 5.0 4.6 8.5 7.8 6.8 5.3 7.0 7.2 y 12.0 8.5 6.0 10.0 12.0 10.0 12.0 10.0 x 5.0 4.6 5.9 7.8 6.4 6.8 5.3 7.2 y 9.5 9.0 11.0 13.0 11.5 12.0 10.0 12.5 x 5.0 4.6 5.9 7.8 6.4 6.8 5.3 7.2 y 9.5 9.0 11.0 13.0 11.5 12.0 10.0 12.5 x 5.0 4.6 8.5 7.8 6.4 6.8 7.0 7.2 y 3.7 2.7 6.5 2.0 5.6 3.0 7.8 6.7 x 5.0 4.6 8.5 7.8 6.4 6.8 7.0 7.2 y 3.7 2.7 6.5 2.0 5.6 3.0 7.8 6.7 x 5.0 4.6 8.5 5.9 7.8 5.3 7.0 7.2 y 12.0 9.0 15.0 11.0 13.0 8.0 14.5 10.0

1 answer

To determine which scatterplot shows a linear association based on the given data, let's analyze the provided datasets individually.

Dataset 1:

  • x: 5.0, 4.6, 8.5, 7.8, 6.8, 5.3, 7.0, 7.2
  • y: 12.0, 8.5, 6.0, 10.0, 12.0, 10.0, 12.0, 10.0

Dataset 2:

  • x: 5.0, 4.6, 5.9, 7.8, 6.4, 6.8, 5.3, 7.2
  • y: 9.5, 9.0, 11.0, 13.0, 11.5, 12.0, 10.0, 12.5

Dataset 3:

  • x: 5.0, 4.6, 8.5, 7.8, 6.4, 6.8, 7.0, 7.2
  • y: 3.7, 2.7, 6.5, 2.0, 5.6, 3.0, 7.8, 6.7

Dataset 4:

  • x: 5.0, 4.6, 8.5, 5.9, 7.8, 5.3, 7.0, 7.2
  • y: 12.0, 9.0, 15.0, 11.0, 13.0, 8.0, 14.5, 10.0

Analysis:

  1. Dataset 1:

    • The y-values are somewhat uneven with no clear increasing or decreasing trend; they seem to fluctuate. Thus, it does not appear to show a linear association.
  2. Dataset 2:

    • The y-values increase steadily as x increases, showing a clear positive trend. This suggests a linear association.
  3. Dataset 3:

    • The y-values fluctuate without an apparent increasing or decreasing trend, indicating no linear association.
  4. Dataset 4:

    • While there are some fluctuations, there are points that increase and decrease in a somewhat less clear pattern. Thus, it does not exhibit a strong linear association.

Conclusion:

Dataset 2 shows a clear linear association in the scatterplot. To visualize this, you would plot x against y for each dataset and look for a straight line pattern to confirm this conclusion.