To determine which dataset has a larger average deviation, we calculate the average deviation for both tables.
Table 1:
- Distance from Mean: 0, 4, 2, 1, 0, 1, 1, 1, 2
- To find the average deviation, we sum these distances and divide by the number of data points.
Sum of distances = \(0 + 4 + 2 + 1 + 0 + 1 + 1 + 1 + 2 = 12\)
Number of data points = 9
Average deviation for Table 1 = \(\frac{12}{9} \approx 1.33\)
Table 2:
- Distance from Mean: 2, 1, 3, 3, 1, 1, 1, 1, 2
- We again sum these distances and divide by the number of data points.
Sum of distances = \(2 + 1 + 3 + 3 + 1 + 1 + 1 + 1 + 2 = 15\)
Number of data points = 9
Average deviation for Table 2 = \(\frac{15}{9} \approx 1.67\)
Now, comparing the average deviations:
- Table 1 average deviation ≈ 1.33
- Table 2 average deviation ≈ 1.67
Thus, we can conclude:
The second table has a larger average deviation.