To compare the average deviations of the two datasets, we need to compute the average deviation for each table.
Table 1:
- Distance from Mean: 0, 4, 2, 1, 0, 1, 1, 1, 2
- Sum of distances from the mean = 0 + 4 + 2 + 1 + 0 + 1 + 1 + 1 + 2 = 12
- Number of data points = 9
- Average deviation = Sum of distances / Number of data points = 12 / 9 ≈ 1.33
Table 2:
- Distance from Mean: 2, 1, 3, 3, 1, 1, 1, 1, 2
- Sum of distances from the mean = 2 + 1 + 3 + 3 + 1 + 1 + 1 + 1 + 2 = 15
- Number of data points = 9
- Average deviation = Sum of distances / Number of data points = 15 / 9 ≈ 1.67
Now we can compare the average deviations:
- Table 1 average deviation ≈ 1.33
- Table 2 average deviation ≈ 1.67
Conclusion: The average deviation of the second table is larger.
Thus, the correct response is: The second table has a larger average deviation.