To find the rate of change (slope, \(m\)) and the initial value (y-intercept, \(b\)) of a linear function from a table of values, we can use the values given in the table:
- For \(x = -5\), \(y = 8\)
- For \(x = -7\), \(y = 14\)
First, we calculate the rate of change (slope, \(m\)): \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Using the points \((-5, 8)\) and \((-7, 14)\):
- \(y_1 = 8\), \(x_1 = -5\)
- \(y_2 = 14\), \(x_2 = -7\)
Substituting in the values: \[ m = \frac{14 - 8}{-7 - (-5)} = \frac{6}{-2} = -3 \]
Next, we can use the slope and one of the points to find the y-intercept (\(b\)) using the equation of a line in slope-intercept form, \(y = mx + b\). We can use the point \((-5, 8)\): \[ 8 = -3(-5) + b \] \[ 8 = 15 + b \] \[ b = 8 - 15 = -7 \]
Thus, \(m = -3\) and \(b = -7\). Therefore, the rate of change and the initial value of the function are: \[ m = -3, b = -7 \]
The correct response is: m = -3, b = -7.