To find the equation of the linear function that models the relationship shown in the table, we can use the two points given: (4, 38) and (6, 58).
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Calculate the slope (m) using the formula \( m = \frac{y_2 - y_1}{x_2 - x_1} \):
Let \( (x_1, y_1) = (4, 38) \) and \( (x_2, y_2) = (6, 58) \).
\[ m = \frac{58 - 38}{6 - 4} = \frac{20}{2} = 10 \]
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Use the slope-intercept form \( y = mx + b \). We already have \( m = 10 \), so we plug that into the equation:
\[ y = 10x + b \]
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Substitute one of the points to find \( b \). Using the point (4, 38):
\[ 38 = 10(4) + b \]
\[ 38 = 40 + b \]
\[ b = 38 - 40 = -2 \]
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Write the final equation:
\[ y = 10x - 2 \]
So the correct response is:
y = 10x - 2.