To find the equation of the linear function from the points in the table, we can use the coordinates provided: (4, 38) and (6, 58).
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Calculate the slope (m): \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{58 - 38}{6 - 4} = \frac{20}{2} = 10 \]
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Use the point-slope form of the equation of a line: The point-slope form is given by: \[ y - y_1 = m(x - x_1) \] Using the point (4, 38): \[ y - 38 = 10(x - 4) \]
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Simplify the equation: \[ y - 38 = 10x - 40 \] \[ y = 10x - 2 \]
Thus, the equation of the linear function that models the relationship shown in the table is: \[ \boxed{y = 10x - 2} \]